05瓯信算面向对象实验

返回“面向对象程序设计课程”

05瓯信算面向对象实验

先打开实验报告模板,查看需要完成哪些题目,然后打开判题系统地址,在判题系统上做对相应题目,最后将正确的程序复制到实验报告中,发到邮箱。

判题系统地址:http://wzuacm.3322.org/

完成如下实验报告:

在实验报告文件名后添加你的学号姓名,比如“面向对象实验1-0530215288-张三.doc”,然后email到: czk.cpp@gmail.com

实验3

  1. 拷贝5.4节中的程序:

       #define ALLOCSIZE 10000 /* size of available space */
    
       static char allocbuf[ALLOCSIZE]; /* storage for alloc */
       static char *allocp = allocbuf;  /* next free position */
    
       char *alloc(int n)    /* return pointer to n characters */
       {
           if (allocbuf + ALLOCSIZE - allocp >= n) {  /* it fits */
               allocp += n;
               return allocp - n; /* old p */
           } else      /* not enough room */
               return 0;
       }
    
       void afree(char *p)  /* free storage pointed to by p */
       {
           if (p >= allocbuf && p < allocbuf + ALLOCSIZE)
               allocp = p;
       }

    或者可以将后面出现的alloc函数调用改成malloc函数调用

  2. 1.9节getline

      /* getline:  read a line into s, return length  */
       int getline(char s[],int lim)
       {
           int c, i;
    
           for (i=0; i < lim-1 && (c=getchar())!=EOF && c!='\n'; ++i)
               s[i] = c;
           if (c == '\n') {
               s[i] = c;
               ++i;
           }
           s[i] = '\0';
           return i;
       }
  3. 5.6节

       #include <stdio.h>
       #include <string.h>
    
       #define MAXLINES 5000     /* max #lines to be sorted */
    
       char *lineptr[MAXLINES];  /* pointers to text lines */
    
       int readlines(char *lineptr[], int nlines);
       void writelines(char *lineptr[], int nlines);
    
       void qsort(char *lineptr[], int left, int right);
    
       /* sort input lines */
       main()
       {
           int nlines;     /* number of input lines read */
    
           if ((nlines = readlines(lineptr, MAXLINES)) >= 0) {
               qsort(lineptr, 0, nlines-1);
               writelines(lineptr, nlines);
               return 0;
           } else {
               printf("error: input too big to sort\n");
               return 1;
           }
       }
    
       #define MAXLEN 1000  /* max length of any input line */
       int getline(char *, int);
       char *alloc(int);
    
       /* readlines:  read input lines */
       int readlines(char *lineptr[], int maxlines)
       {
           int len, nlines;
           char *p, line[MAXLEN];
    
           nlines = 0;
           while ((len = getline(line, MAXLEN)) > 0)
               if (nlines >= maxlines || (p = alloc(len)) == NULL)
                   return -1;
               else {
                   line[len-1] = '\0';  /* delete newline */
                   strcpy(p, line);
                   lineptr[nlines++] = p;
               }
           return nlines;
       }
    
       /* writelines:  write output lines */
       void writelines(char *lineptr[], int nlines)
       {
           int i;
    
           for (i = 0; i < nlines; i++)
               printf("%s\n", lineptr[i]);
       }

    及qsort和swap

    void qsort(char *v[], int left, int right)
    {
        int i, last;
        void swap(char *v[], int i, int j);
    
        if (left >= right)  /* do nothing if array contains */
            return;         /* fewer than two elements */
        swap(v, left, (left + right)/2);
        last = left;
        for (i = left+1; i <= right; i++)
            if (strcmp(v[i], v[left]) < 0)
                swap(v, ++last, i);
        swap(v, left, last);
        qsort(v, left, last-1);
        qsort(v, last+1, right);
    }
    /* swap:  interchange v[i] and v[j] */
    void swap(char *v[], int i, int j)
    {
        char *temp;
    
        temp = v[i];
        v[i] = v[j];
        v[j] = temp;
    }
  4. 所有的qsort换一个名字,比如qsort2

  5. 修改readlines函数

        while(scanf("%s", line)!=EOF) {
            len = strlen(line)+1;

实验6

基础知识参看:C++类与对象

实验7

相关基础知识:C++继承与多态